0=2x^2-15x-24

Solution for 0=2x^2-15x-24 equation:

0=2x^2-15x-24

We move all terms to the left:

0-(2x^2-15x-24)=0

We add all the numbers together, and all the variables

-(2x^2-15x-24)=0

We get rid of parentheses

-2x^2+15x+24=0

a = -2; b = 15; c = +24;
Δ = b2-4ac
Δ = 152-4·(-2)·24
Δ = 417
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{417}}{2*-2}=\frac{-15-\sqrt{417}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{417}}{2*-2}=\frac{-15+\sqrt{417}}{-4}
$